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    Emf, Maximum Power and Efficiency of Fuel Cells

    Source: Journal of Energy Resources Technology:;1993:;volume( 115 ):;issue: 002::page 100
    Author:
    R. A. Gaggioli
    ,
    W. R. Dunbar
    DOI: 10.1115/1.2905975
    Publisher: The American Society of Mechanical Engineers (ASME)
    Abstract: The ideal voltage of steady-flow fuel cells is usually expressed by Emf = −ΔG°/nF where ΔG° is the “Gibbs free energy of reaction” for the oxidation of the fuel at the supposed temperature of operation of the cell. Furthermore, the ideal power of the cell is expressed as the product of the fuel flow rate with this emf. Such viewpoints are flawed in several respects. While it is true that if a cell operates isothermally, the maximum conceivable electrical work output is equal to the difference between the Gibbs free energy of the incoming reactants and that of the leaving products; nevertheless, even if the cell operates isothermally, the use of the conventional ΔG° of reaction (a) assumes that the products of reaction leave separately from one another (and from any unused fuel); and (b) when ΔS of reaction is positive, it assumes that a free heat source exists at the operating temperature, whereas if ΔS is negative, it neglects the potential power which theoretically could be obtained from the heat released during oxidation. Moveover, (c) the usual cell does not operate isothermally, but (virtually) adiabatically. Comment (a) is often accounted for by employing the Nernst equation to correct for the dilution of reactants and/or products. Nevertheless, comments (b) and (c) remain pertinent. Rather than with emf, the proper starting place is with power output. The ideal power is that which would be obtained if the fuel were oxidized without irreversible entropy generation. Among other factors, this ideal power output depends upon the ratio of oxidant to fuel flow rate (e.g., air-fuel ratio) and the percentage of fuel oxidation. The ideal voltage is deduced from the ideal power, because it is defined as electrical work output per unit of charge delivered. It is a local characteristic which varies with the percent of fuel oxidized. Therefore, (d) ideal power is not equal to the product of emf with current (unless the amount of fuel utilized is infinitesimal). Examples are presented which illustrate such affects and their importance for the evaluation of ideal power and of efficiency.
    keyword(s): Fuel cells , Fuels , Flow (Dynamics) , oxidation , Heat , Electric potential , Gibbs' free energy , Equations , Fatigue life , Temperature , Entropy AND Operating temperature ,
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      Emf, Maximum Power and Efficiency of Fuel Cells

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    contributor authorR. A. Gaggioli
    contributor authorW. R. Dunbar
    date accessioned2017-05-08T23:41:10Z
    date available2017-05-08T23:41:10Z
    date copyrightJune, 1993
    date issued1993
    identifier issn0195-0738
    identifier otherJERTD2-26449#100_1.pdf
    identifier urihttp://yetl.yabesh.ir/yetl/handle/yetl/111840
    description abstractThe ideal voltage of steady-flow fuel cells is usually expressed by Emf = −ΔG°/nF where ΔG° is the “Gibbs free energy of reaction” for the oxidation of the fuel at the supposed temperature of operation of the cell. Furthermore, the ideal power of the cell is expressed as the product of the fuel flow rate with this emf. Such viewpoints are flawed in several respects. While it is true that if a cell operates isothermally, the maximum conceivable electrical work output is equal to the difference between the Gibbs free energy of the incoming reactants and that of the leaving products; nevertheless, even if the cell operates isothermally, the use of the conventional ΔG° of reaction (a) assumes that the products of reaction leave separately from one another (and from any unused fuel); and (b) when ΔS of reaction is positive, it assumes that a free heat source exists at the operating temperature, whereas if ΔS is negative, it neglects the potential power which theoretically could be obtained from the heat released during oxidation. Moveover, (c) the usual cell does not operate isothermally, but (virtually) adiabatically. Comment (a) is often accounted for by employing the Nernst equation to correct for the dilution of reactants and/or products. Nevertheless, comments (b) and (c) remain pertinent. Rather than with emf, the proper starting place is with power output. The ideal power is that which would be obtained if the fuel were oxidized without irreversible entropy generation. Among other factors, this ideal power output depends upon the ratio of oxidant to fuel flow rate (e.g., air-fuel ratio) and the percentage of fuel oxidation. The ideal voltage is deduced from the ideal power, because it is defined as electrical work output per unit of charge delivered. It is a local characteristic which varies with the percent of fuel oxidized. Therefore, (d) ideal power is not equal to the product of emf with current (unless the amount of fuel utilized is infinitesimal). Examples are presented which illustrate such affects and their importance for the evaluation of ideal power and of efficiency.
    publisherThe American Society of Mechanical Engineers (ASME)
    titleEmf, Maximum Power and Efficiency of Fuel Cells
    typeJournal Paper
    journal volume115
    journal issue2
    journal titleJournal of Energy Resources Technology
    identifier doi10.1115/1.2905975
    journal fristpage100
    journal lastpage104
    identifier eissn1528-8994
    keywordsFuel cells
    keywordsFuels
    keywordsFlow (Dynamics)
    keywordsoxidation
    keywordsHeat
    keywordsElectric potential
    keywordsGibbs' free energy
    keywordsEquations
    keywordsFatigue life
    keywordsTemperature
    keywordsEntropy AND Operating temperature
    treeJournal of Energy Resources Technology:;1993:;volume( 115 ):;issue: 002
    contenttypeFulltext
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